If it's not what You are looking for type in the equation solver your own equation and let us solve it.
(3n^2)+16n-12=0
a = 3; b = 16; c = -12;
Δ = b2-4ac
Δ = 162-4·3·(-12)
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{400}=20$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-20}{2*3}=\frac{-36}{6} =-6 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+20}{2*3}=\frac{4}{6} =2/3 $
| 5m-7=2m+8 | | 5(8n=8)=-8n-8 | | 10u-21=3 | | 8(3a+6=9(2a-4 | | 18=(x÷4)+x | | -1-3(n-1)=3n+26 | | -7-4(6k+5)=5k+31 | | K(-3)=4x+1 | | -20+4y=4y | | -12(s+4)=60 | | -5x-3(2x+17)=15 | | -2/3(9x-6)=14 | | a=5a-8a | | 2–6m+5=m+7 | | -5x+18x=-13 | | 2.8+.9x=4+x | | -4p-6(8-3p)=4p+22 | | -6(3-4x)+2x=-96 | | H(-4)=0.5x-14 | | -364=-7(8v+4) | | 2^4x-12=16 | | 5x-4(-3x-5)=-167 | | -86=2(1-5r)-8 | | 5(8m-3)=225 | | 1/3x+5=10 | | -7-6(-x-3)=24 | | 7(-5m+5)-3m=111 | | F(8)=-3x+20 | | F(8)=-3x* | | -96=5(-5-5n)+4 | | 8-(4x+7)=5(x=6)-1 | | 3x+5+x+3=180 |